Digital Electronics - Combinational Logic Analysis - Discussion
Discussion Forum : Combinational Logic Analysis - Filling the Blanks (Q.No. 1)
1.
Assume you have A, B, C, and D available but not their complements. The minimum number of 2-input NAND gates required to implement the equation 
is ________.
is ________.Discussion:
6 comments Page 1 of 1.
Neha said:
8 years ago
Thank You @Jyothi.
Jyothi said:
8 years ago
We can write this eq as AA'+AB'+BB'+BC' bcoz AA'=0 then again we simply this eq as A(A'+B')+B(B'+C').
We need 1NAND gate for A'+B'.
For A(A'+B') 1NAND.
For B'+C' 1NAND.
For B(B'+C') 1NAND.
FINALLY, FOR THAT EQ WE NEED ANOTHER NAND GATE totally 5NAND GATES.
We need 1NAND gate for A'+B'.
For A(A'+B') 1NAND.
For B'+C' 1NAND.
For B(B'+C') 1NAND.
FINALLY, FOR THAT EQ WE NEED ANOTHER NAND GATE totally 5NAND GATES.
Hanna said:
9 years ago
How? Explain.
Dale said:
10 years ago
How it is five?
Naresh said:
1 decade ago
Explanation?
Bhasker said:
1 decade ago
Elaborate the concept.
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