Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 2 (Q.No. 5)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
| State | Year | |||||||||
| 1997 | 1998 | 1999 | 2000 | 2001 | ||||||
| App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |
| M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |
| N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |
| P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |
| Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |
| R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |
5.
The percentage of total number of qualified candidates to the total number of appeared candidates among all the five states in 1999 is?
Answer: Option
Explanation:
| Required percentage |
|
|||||||
|
||||||||
| = 11.84%. |
![]](/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif)
Discussion:
13 comments Page 2 of 2.
Lionee said:
3 years ago
The total qualified candidates of state N in all years.
= (840+1050+920+980+1020) ÷ (7500+9200+8450+9200+8800)*100
= (4810÷43150)*100,
= 11.147%.
Approximately the answer is 11.15%.
= (840+1050+920+980+1020) ÷ (7500+9200+8450+9200+8800)*100
= (4810÷43150)*100,
= 11.147%.
Approximately the answer is 11.15%.
(8)
Mohan said:
2 years ago
Thank you for explaining the answer @Ananthraj Vijayakumar.
Shivani said:
2 years ago
Not understand this. Please explain me in detail.
(2)
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