# Data Interpretation - Pie Charts - Discussion

Discussion Forum : Pie Charts - Pie Chart 9 (Q.No. 4)

*Directions to Solve*

The circle-graph given here shows the spendings of a country on various sports during a particular year. Study the graph carefully and answer the questions given below it.

4.

How much percent less is spent on Football than that on Cricket?

Answer: Option

Explanation:

Let the total spendings on sports be Rs. *x*. Then,

Amount spent on Cricket = Rs. | 81 | x x |
= Rs. | 9x |
. | ||

360 | 40 |

Amount spent on Football = Rs | 54 | x x |
= Rs. | 3x |
. | ||

360 | 20 |

Difference = Rs. | 9x |
- | 3x |
= Rs | 3x |
. | ||

40 | 20 | 40 |

Required percentage = Rs. | 3x/40 |
x 100 | % = 33 | 1 | %. | ||||

9x/40 |
3 |

Discussion:

9 comments Page 1 of 1.
Lucky said:
2 years ago

It nice to understand. Thank you, everyone.

Prem Tenyoung said:
3 years ago

(81-54)/81*100,

= 33.33.

First, find the difference of cricket and football(81-54=27) Since we wanted to find out football is how much less from cricket we should divide the difference we got with cricket keeping the value of cricket as denominator then multiply with 100 to find percentage (27/81*100 = 33.33).

= 33.33.

First, find the difference of cricket and football(81-54=27) Since we wanted to find out football is how much less from cricket we should divide the difference we got with cricket keeping the value of cricket as denominator then multiply with 100 to find percentage (27/81*100 = 33.33).

(2)

Tan said:
4 years ago

Can anyone explain me the question in detail?

Aribo Adani said:
5 years ago

Nice, Thanks all.

Sushmitha said:
6 years ago

Please explain the answer.

Rajendra said:
7 years ago

I would consider this question as for whether there is a growth or decline in two values relative to any one value of the two and that how much in %?

Here, we have two categories, Cricket 81 degree & Football 54 degree.

Whether the two values here are in degrees or percentage, the conclusion is that these show the share in total amount, hence, no need to convert into a percent, first.

Secondly, we need the absolute difference in two values i.e. |81 - 54| = |27|.

Then, we need to define which value we need to find growth /decline, as Cricket is here,

hence, we will simply divide the difference by Cricket share value = 27/81 = 0.333333, multiply by 100 for a percentile of the division = 33.34% (now, what we understand by 33 of 100 is 1/3rd, i.e. we get 33 1/3% less expenditure on Football compared to Cricket.

Here, we have two categories, Cricket 81 degree & Football 54 degree.

Whether the two values here are in degrees or percentage, the conclusion is that these show the share in total amount, hence, no need to convert into a percent, first.

Secondly, we need the absolute difference in two values i.e. |81 - 54| = |27|.

Then, we need to define which value we need to find growth /decline, as Cricket is here,

hence, we will simply divide the difference by Cricket share value = 27/81 = 0.333333, multiply by 100 for a percentile of the division = 33.34% (now, what we understand by 33 of 100 is 1/3rd, i.e. we get 33 1/3% less expenditure on Football compared to Cricket.

NARESH said:
8 years ago

(Cricket - Football / Cricket)/100.

= (81 - 54/81) * 100.

= 33.33.

= (81 - 54/81) * 100.

= 33.33.

Mahendra singh said:
1 decade ago

We can simply do this by 81-54 = 27.

27*100/81 = 100/3.

Keep in mind always that we calculate this type of question then we must take the denominator to that on.

27*100/81 = 100/3.

Keep in mind always that we calculate this type of question then we must take the denominator to that on.

Dev said:
1 decade ago

((cricket-football)/cricket)*100

(27/81)*100=33.333.

if v wana find lesser percent hav to put greater amnt at denominator.thats wat v done here if it s greater amnt hav to put lesser amnt at denominator i think v done this at fist question of same prob.

(27/81)*100=33.333.

if v wana find lesser percent hav to put greater amnt at denominator.thats wat v done here if it s greater amnt hav to put lesser amnt at denominator i think v done this at fist question of same prob.

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