Data Interpretation - Line Charts - Discussion
Discussion Forum : Line Charts - Line Chart 5 (Q.No. 5)
Directions to Solve
The following line graph gives the percentage of the number of candidates who qualified an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.
Percentage of Candidates Qualified to Appeared in an Examination Over the Years
5.
The total number of candidates qualified in 1999 and 2000 together was 33500 and the number of candidates appeared in 1999 was 26500. What was the number of candidates in 2000?
Answer: Option
Explanation:
The number of candidates qualified in 1999 = (80% of 26500) = 21200.
Number of candidates qualified in 2000 = (33500 - 21200) = 12300.
Let the number of candidates appeared in 2000 be x.
Then, 60% of x = 12300  x = |
 |
12300 x 100 |  |
= 20500. |
| 60 |
Discussion:
7 comments Page 1 of 1.
Deepu said:
5 years ago
First know the formula,
Percentage = (Qualified /Appeared)x 100.
Given in 1999 candidates appeared was 26500 and from graph percentage in 1999 is 80
Therefore using above formula,
80 = (Q/26500)x 100.
Q in 1999 =21200.
And also given candidate qualified in both years is 33500.
Therefore,
Q(1999)+Q(2000) = 33500.
Q(2000)=33500-21200 = 12300.
They asked to find number of candidates in 2000 means they are asking appeared candidates
Again use above percentage formula,
60 = (12300/A)x100.
A = 20500.
Percentage = (Qualified /Appeared)x 100.
Given in 1999 candidates appeared was 26500 and from graph percentage in 1999 is 80
Therefore using above formula,
80 = (Q/26500)x 100.
Q in 1999 =21200.
And also given candidate qualified in both years is 33500.
Therefore,
Q(1999)+Q(2000) = 33500.
Q(2000)=33500-21200 = 12300.
They asked to find number of candidates in 2000 means they are asking appeared candidates
Again use above percentage formula,
60 = (12300/A)x100.
A = 20500.
(1)
Todje said:
1 decade ago
The number of students that qualified is LESS than the number of students who appeared (that is, those who turned up to take the exam they were eligible for). This makes no sense!?
Hardik Chawda said:
1 decade ago
Please Resolve my Doubts.
x = Digital Sum(12300) X D.Sum(100)/D.Sum(60).
= D.Sum(6X1)/D.Sum(6) = 1.
Eliminate click option D in which case D, sum should be used.
x = Digital Sum(12300) X D.Sum(100)/D.Sum(60).
= D.Sum(6X1)/D.Sum(6) = 1.
Eliminate click option D in which case D, sum should be used.
Mohammd aiyoob said:
6 years ago
Can you please explain to me with detailed how 80% of 26500=21200?
I did not understand this step.
I did not understand this step.
Jyothi said:
9 years ago
Can you please explain me with detailed how 80% of 26500=21200?
I did not understand this step.
I did not understand this step.
BALAJI BALAJI said:
8 years ago
80/100 * 26500 = 21200.
Aditi said:
6 years ago
26500*80/100 = 21200.
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