# Data Interpretation - Bar Charts - Discussion

Discussion Forum : Bar Charts - Bar Chart 14 (Q.No. 1)
Directions to Solve

The following chart represents the number of students who passed the CAT exam or the XAT exam or the CET exam or None of these exams. (Assume that there are no students who passed more than one exam.)

Number of students who qualified CAT/XAT/CET Exams

1.
Which year showed the best result in MBA entrance exams (in terms of percentage of students who cleared) ?
2000
2001
2002
Cannot be determined
Explanation:

Compare the respective pass percentage for three years : 2000, 2001 and 2002

= (140 x 100)/170 < (150 x 100)/180 and (150 x 100)/180 > (160 x 100)/200

= 82.35% < 83.33% and 83.33% > 80%

Discussion:
9 comments Page 1 of 1.

Cherry said:   9 years ago
Can any one explain it clearly please?

Ramakanth said:   9 years ago
@Cherry:

In the year 2000 total no.of students appeared for the exam was 170. Out of those 140 cleared the exam. Hence the percentage will be 140/170*100.

Similarly calculate the percentages for the remaining two years.

Anjli said:   8 years ago
Why you take 170, 180 and 200 for the division?

Anaya said:   7 years ago
@Anjli.

Because we want to see % of students qualified in the exam hence 170, 180, 200 was considered.

Jemimah said:   6 years ago
How comes 140, 150, 160? please explain.

Navya said:   3 years ago
Here it is asked the best result so none should not be considered.
So 140/170 * 100.

Nikhil said:   3 years ago
In the chart where it is mentioned about MBA. Can anyone specify?
(1)

Kiran said:   2 years ago
@All.

In terms of the percentage of students who cleared

For year 2000,
Number of students who qualified(or passed) CAT/XAT/CET Exams = 140,
Total number of students passed and none = 170,
% = (140/170) * 100.
Hope this helps!

Sagarika deb said:   1 week ago
How it is 170came?