Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 3 (Q.No. 8)
8.
You have a network ID of 134.57.0.0 and you need to divide it into multiple subnets in which at least 600 host IDs for each subnet are available. You desire to have the largest amount of subnets available. Which subnet mask should you assign?
Discussion:
13 comments Page 1 of 2.
GURPREET SINGH said:
10 years ago
You have a network ID of 134.57.0.0 and you need to divide it into multiple subnets in which at least 600 host IDs for each subnet are available. You desire to have the largest amount of subnets available. Which subnet mask should you assign?
IP belongs to class B. So 255.255.0.0 mask and for that 16 bits.
Remaining bits are 16 out of 16, and now we want 600 host per subnet for that we required 10 bit for host.
So, mask becomes 1111 1111.1111 1111.1111 1100.0000 0000 for subnet 134.57.252.0. is a correct answer.
IP belongs to class B. So 255.255.0.0 mask and for that 16 bits.
Remaining bits are 16 out of 16, and now we want 600 host per subnet for that we required 10 bit for host.
So, mask becomes 1111 1111.1111 1111.1111 1100.0000 0000 for subnet 134.57.252.0. is a correct answer.
(1)
Yogesh said:
9 years ago
255.255.255.252 will be the answer.
10 bits would be in host part.
10 bits would be in host part.
(1)
Pakhi said:
4 years ago
But guys I have a doubt the method which you are using is for the given subnets not for the given hosts.
In question, there is 600 hosts, not 600 subnet.
Anyone, please clarify this.
In question, there is 600 hosts, not 600 subnet.
Anyone, please clarify this.
(1)
Elias Ahmed said:
2 years ago
According to me, the correct answer will be 255.255.252.0.
(1)
Ravi kumar said:
1 decade ago
Given IP belongs to class B.
we need 600 host...means >2^9(greater than 512).
Hence we need at least 10 bit.but in option C
255.255.255.0
Binary form 11111111.11111111.11111111.00000000
we have only 8 bit(zero's which define No. of Host).so it will give 254(256-2)per host.
correct answer C.
as 255.255.248.0
Binary Form 11111111.11111111.11111000.00000000
So we have 11 bit (2^11-2=2046) or 2046 per subnet(total subnet=32=2^5).
we need 600 host...means >2^9(greater than 512).
Hence we need at least 10 bit.but in option C
255.255.255.0
Binary form 11111111.11111111.11111111.00000000
we have only 8 bit(zero's which define No. of Host).so it will give 254(256-2)per host.
correct answer C.
as 255.255.248.0
Binary Form 11111111.11111111.11111000.00000000
So we have 11 bit (2^11-2=2046) or 2046 per subnet(total subnet=32=2^5).
Chetana Tailor said:
1 decade ago
You have a network ID of 134.57.0.0 and you need to divide it into multiple subnets in which at least 600 host IDs for each subnet are available. You desire to have the largest amount of subnets available. Which subnet mask should you assign?
IP belongs to class B so 255.255.0.0 mask and for that 16 bits.
remaining bits are 16 out of 16, and now we want 600 host per subnet for that we required 10 bit for host.
So, mask becomes 1111 1111.1111 1111.1111 1100.0000 0000 for subnet
134.57.252.0.
IP belongs to class B so 255.255.0.0 mask and for that 16 bits.
remaining bits are 16 out of 16, and now we want 600 host per subnet for that we required 10 bit for host.
So, mask becomes 1111 1111.1111 1111.1111 1100.0000 0000 for subnet
134.57.252.0.
Mansoor said:
1 decade ago
@Chetana Tailor.
This subnet mask is not given in the options, Why is it mistake in the given options?
This subnet mask is not given in the options, Why is it mistake in the given options?
Chetan said:
9 years ago
The answer is wrong because at least 600 hosts mean we need more than 9 bits that are 10 bit. So the subnet should be 255.255.252.0 and less than 252. So if we go with the option than maximum subnet option will be C that is 248.
GS Baloch said:
9 years ago
The correct answer is 255.255.252.0.
But it is not in the given options.
But it is not in the given options.
Yogesh Singh said:
8 years ago
255.255.252.0 is correct as 10 bits for required host.
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