Computer Science - Networking - Discussion

According to me, the correct answer will be 255.255.252.0.

But guys I have a doubt the method which you are using is for the given subnets not for the given hosts.

In question, there is 600 hosts, not 600 subnet.

Anyone, please clarify this.

Yes, the correct answer is 255.255.252.0 as minimum 10 bits are required in host ID part to have at least 600 hosts.

(2^10-2=1022, 2^9 -2 =512 (does not satisfy 600 hosts).

6 bits in network ID makes a mask of 252 in third octet of class B.

The answer will be 255.255.252.0.

255.255.252.0 is correct as 10 bits for required host.

The correct answer is option C.

The correct answer is 255.255.252.0.

But it is not in the given options.

255.255.255.252 will be the answer.

10 bits would be in host part.

The answer is wrong because at least 600 hosts mean we need more than 9 bits that are 10 bit. So the subnet should be 255.255.252.0 and less than 252. So if we go with the option than maximum subnet option will be C that is 248.

You have a network ID of 134.57.0.0 and you need to divide it into multiple subnets in which at least 600 host IDs for each subnet are available. You desire to have the largest amount of subnets available. Which subnet mask should you assign?

IP belongs to class B. So 255.255.0.0 mask and for that 16 bits.

Remaining bits are 16 out of 16, and now we want 600 host per subnet for that we required 10 bit for host.

So, mask becomes 1111 1111.1111 1111.1111 1100.0000 0000 for subnet 134.57.252.0. is a correct answer.