Computer Science - Networking - Discussion

Discussion Forum : Networking - Section 1 (Q.No. 28)
28.
What part of 192.168.10.51 is the Network ID, assuming a default subnet mask?
192
192.168.10
0.0.0.5
51
None of the above
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Shailesh Saxena said:   6 years ago
Class A: IP address range from 0-127 in the first byte designed for very large companies.

Class B: IP address range from 128-191 in the first byte designed for medium-size companies.

Class C: IP address range from 192-223 in the first byte designed for small companies.

Class D: IP address range from 224-239 in the first byte reserved for multicast addressing. Not used in the public sector.

Class E: IP address range from 240-255 in the first byte reserved for scientific studies. Not used in the public sector.

Jasma said:   7 years ago
The default mask is 255 means take same above value for calculation of AND operation.

Md.Rafi said:   8 years ago
C class Subnet Mask.

Default Mask 255.255.255.0.
So this answer:192.168.10.

Malay said:   1 decade ago
How it is class network please explain?

Vimy Sarcar said:   1 decade ago
Here The Last Mask Has Been Not Full on The Live the Desk than Its Associate With The C.

Now 192.168.10.51

Than Default Mask 255.255.255.0

Only Consider Empty Blogs than 192.168.10.0

192.168.10

Muhammad pv said:   1 decade ago
192.168.10.51 is in Class C..so its default subnet mask is 255.255.255.0. so taking binary of both and apply AND operation
We get 192.168.10
(1)

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