Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 1 (Q.No. 3)
3.
The probability that a single bit will be in error on a typical public telephone line using 4800 bps modem is 10 to the power -3. If no error detection mechanism is used, the residual error rate for a communication line using 9-bit frames is approximately equal to
Discussion:
9 comments Page 1 of 1.
Aniruddha said:
1 decade ago
Here the data rate of 4800 bps is redundant information.
Probability that a single bit is in error 10^-3 = 0.001t
Probability that a single bit is not in error = 1 - 0.001 = 0.999
In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.
Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)
Probability that a single bit is in error 10^-3 = 0.001t
Probability that a single bit is not in error = 1 - 0.001 = 0.999
In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.
Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)
P.tarun said:
1 decade ago
Here the data rate of 4800 bps is redundant information.
Probability that a single bit is in error 10^-3 = 0.001t
Probability that a single bit is not in error = 1 - 0.001 = 0.999
In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.
Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)
Probability that a single bit is in error 10^-3 = 0.001t
Probability that a single bit is not in error = 1 - 0.001 = 0.999
In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.
Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)
(5)
Sagar said:
1 decade ago
Thus, chances that all 9 bits are correct = 0.999*9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)
(1)
Shivakumar_bpt said:
9 years ago
Probability that a single bit is in error 10^-3 = 0.001t.
Probability that a single bit is not in error = 1 - 0.001 = 0.999.
Probability that a single bit is not in error = 1 - 0.001 = 0.999.
(1)
Dipayan Das said:
1 decade ago
1bit error probability 1/1000
9bit error probability 9/1000
.ie .009
9bit error probability 9/1000
.ie .009
Suresh kumar said:
1 decade ago
What is the method/theory to solve this question?
Geetu said:
10 years ago
Please tell me how can I easily solve?
Laxmi kant said:
1 decade ago
Please explain the answer.
M.venkat said:
1 decade ago
1-1/1000
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