# Computer Science - Networking - Discussion

Discussion Forum : Networking - Section 1 (Q.No. 3)

3.

The probability that a single bit will be in error on a typical public telephone line using 4800 bps modem is 10 to the power -3. If no error detection mechanism is used, the residual error rate for a communication line using 9-bit frames is approximately equal to

Discussion:

9 comments Page 1 of 1.
Shivakumar_bpt said:
7 years ago

Probability that a single bit is in error 10^-3 = 0.001t.

Probability that a single bit is not in error = 1 - 0.001 = 0.999.

Probability that a single bit is not in error = 1 - 0.001 = 0.999.

Geetu said:
8 years ago

Please tell me how can I easily solve?

P.tarun said:
1 decade ago

Here the data rate of 4800 bps is redundant information.

Probability that a single bit is in error 10^-3 = 0.001t

Probability that a single bit is not in error = 1 - 0.001 = 0.999

In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.

Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Probability that a single bit is in error 10^-3 = 0.001t

Probability that a single bit is not in error = 1 - 0.001 = 0.999

In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.

Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

(1)

Sagar said:
1 decade ago

Thus, chances that all 9 bits are correct = 0.999*9 = 0.991 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Aniruddha said:
1 decade ago

Here the data rate of 4800 bps is redundant information.

Probability that a single bit is in error 10^-3 = 0.001t

Probability that a single bit is not in error = 1 - 0.001 = 0.999

In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.

Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Probability that a single bit is in error 10^-3 = 0.001t

Probability that a single bit is not in error = 1 - 0.001 = 0.999

In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.

Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Dipayan Das said:
1 decade ago

1bit error probability 1/1000

9bit error probability 9/1000

.ie .009

9bit error probability 9/1000

.ie .009

Suresh kumar said:
1 decade ago

What is the method/theory to solve this question?

M.venkat said:
1 decade ago

1-1/1000

Laxmi kant said:
1 decade ago

Please explain the answer.

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