Computer Science - Networking - Discussion

3. 

The probability that a single bit will be in error on a typical public telephone line using 4800 bps modem is 10 to the power -3. If no error detection mechanism is used, the residual error rate for a communication line using 9-bit frames is approximately equal to

[A]. 0.003
[B]. 0.009
[C]. 0.991
[D]. 0.999
[E]. None of the above

Answer: Option B

Explanation:

No answer description available for this question.

Laxmi Kant said: (Sep 20, 2011)  
Please explain the answer.

M.Venkat said: (Nov 3, 2011)  
1-1/1000

Suresh Kumar said: (Dec 9, 2011)  
What is the method/theory to solve this question?

Dipayan Das said: (Mar 3, 2012)  
1bit error probability 1/1000
9bit error probability 9/1000

.ie .009

Aniruddha said: (Aug 13, 2012)  
Here the data rate of 4800 bps is redundant information.
Probability that a single bit is in error 10^-3 = 0.001t
Probability that a single bit is not in error = 1 - 0.001 = 0.999

In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.

Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Sagar said: (Oct 30, 2012)  
Thus, chances that all 9 bits are correct = 0.999*9 = 0.991 (approx)

Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

P.Tarun said: (Dec 20, 2012)  
Here the data rate of 4800 bps is redundant information.
Probability that a single bit is in error 10^-3 = 0.001t
Probability that a single bit is not in error = 1 - 0.001 = 0.999

In a frame of 9 bits the residual error rate value signifies the probability that at least one of the bits out of the nine is in error.

Thus, chances that all 9 bits are correct = 0.999^9 = 0.991 (approx)
Residual error rate = chances that at least one of 9 bits is incorrect = 1 - 0.991 = 0.009 (approx)

Geetu said: (Aug 9, 2015)  
Please tell me how can I easily solve?

Shivakumar_Bpt said: (Sep 8, 2016)  
Probability that a single bit is in error 10^-3 = 0.001t.

Probability that a single bit is not in error = 1 - 0.001 = 0.999.

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