Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 1 (Q.No. 43)
43.
The expected discharge to be obtained from an open well sunk in coarse sand is 0.0059 cumec. If the working depression head of the well is 3 m, the minimum diameter of the well, is
Discussion:
20 comments Page 1 of 2.
Asad said:
3 years ago
Q=kiA.
Use this formula to get the answer.
Use this formula to get the answer.
(2)
Goutom saikia said:
6 years ago
From open well
Q=kAH
K is 1 /hour for coares sand
Take discarge in meter cube/hour
Area as cross section of circle 3.14*r2
Finally answer comes 3
Q=kAH
K is 1 /hour for coares sand
Take discarge in meter cube/hour
Area as cross section of circle 3.14*r2
Finally answer comes 3
(7)
Girma said:
6 years ago
Thank you all.
(2)
Akki said:
6 years ago
Thanks all for explaining.
Shreedevi said:
6 years ago
Thank you for explaining.
Soumyadip said:
7 years ago
@Nani.
Discharge is converted to m^3/hr because.
(C'/A) value is 1 in m^3/hr/m^2 under unit drawdown,
Q=(C'/A) * A * s.
Q=0.0059 cumec = 21.24 m^3/hr.
S=3.
Hence; A=7.08 m^2.
D= 3.
Discharge is converted to m^3/hr because.
(C'/A) value is 1 in m^3/hr/m^2 under unit drawdown,
Q=(C'/A) * A * s.
Q=0.0059 cumec = 21.24 m^3/hr.
S=3.
Hence; A=7.08 m^2.
D= 3.
(1)
Nani sira said:
7 years ago
Why converting sec to the hour? Please explain.
(1)
Gubendhiran said:
8 years ago
Q=KiA ; i=3m; A = 0.785d^2; K=1 Q=0.0059m^3/sec=21.24m^3/hr.
21.24=1*3*0.785*d^2,
d^2=(21.24)/(3*0.785)=9.0191,
d=3m.
21.24=1*3*0.785*d^2,
d^2=(21.24)/(3*0.785)=9.0191,
d=3m.
(7)
Ashley said:
8 years ago
Please explain it clearly answer is not coming according to above formula.
(1)
Aks p hi said:
8 years ago
@Kevia why did you convert it in m3/hr?
Units is given in cumsec (m3/s).
Answer is coming 0.050 according to formula.
Units is given in cumsec (m3/s).
Answer is coming 0.050 according to formula.
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