Discussion :: Water Supply Engineering - Section 1 (Q.No.43)
|Punati said: (Aug 1, 2014)|
|Could you please explain me to solve this problem?|
|Deepli said: (Jun 19, 2015)|
|Please solve this problem.|
|Manoj said: (Aug 22, 2015)|
|What is formula?|
|Mdpawar said: (Dec 3, 2015)|
|How to solve this problem?|
|Sahil Upadhyay Ggmu said: (May 3, 2016)|
|This can be solved by:
Q = (K/A).A.H.
|Vijay said: (Jul 26, 2016)|
|Please give the clear solution of this problem.|
|Laxmipriya Dhal said: (Oct 24, 2016)|
|@Sahil, What is the value of k?|
|Ganesh Mahale said: (Nov 13, 2016)|
|Depression head calculation from formula Q = K H Where k = 1 for course grain soil, 0.5 for fine sand and 0.25 for clay.
For this case, k =1 thus, Q=3.
|Kevia said: (Nov 16, 2016)|
|Q = (k/A) * A * H
For coarse sand, k/A = 1,
For fine sand, k/A = 0.5,
For clay, k/A = 0.25.
Q = 0.0059 m^3/sec,
Q = 0.0059 * 60 * 60 m^3/hour,
A = (pi/4) * d^2.
|Rama said: (Aug 25, 2017)|
|Aks P Hi said: (Oct 31, 2017)|
|@Kevia why did you convert it in m3/hr?
Units is given in cumsec (m3/s).
Answer is coming 0.050 according to formula.
|Ashley said: (Nov 2, 2017)|
|Please explain it clearly answer is not coming according to above formula.|
|Gubendhiran said: (Dec 30, 2017)|
|Q=KiA ; i=3m; A = 0.785d^2; K=1 Q=0.0059m^3/sec=21.24m^3/hr.
|Nani Sira said: (May 18, 2018)|
|Why converting sec to the hour? Please explain.|
|Soumyadip said: (Nov 2, 2018)|
Discharge is converted to m^3/hr because.
(C'/A) value is 1 in m^3/hr/m^2 under unit drawdown,
Q=(C'/A) * A * s.
Q=0.0059 cumec = 21.24 m^3/hr.
Hence; A=7.08 m^2.
|Shreedevi said: (May 16, 2019)|
|Thank you for explaining.|
|Akki said: (May 24, 2019)|
|Thanks all for explaining.|
|Girma said: (Aug 5, 2019)|
|Thank you all.|
|Goutom Saikia said: (Oct 2, 2019)|
|From open well
K is 1 /hour for coares sand
Take discarge in meter cube/hour
Area as cross section of circle 3.14*r2
Finally answer comes 3
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