Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 1 (Q.No. 43)
43.
The expected discharge to be obtained from an open well sunk in coarse sand is 0.0059 cumec. If the working depression head of the well is 3 m, the minimum diameter of the well, is
Discussion:
20 comments Page 2 of 2.
Rama said:
8 years ago
Thanks @Kevia.
Kevia said:
9 years ago
Q = (k/A) * A * H
For coarse sand, k/A = 1,
For fine sand, k/A = 0.5,
For clay, k/A = 0.25.
Q = 0.0059 m^3/sec,
Q = 0.0059 * 60 * 60 m^3/hour,
A = (pi/4) * d^2.
For coarse sand, k/A = 1,
For fine sand, k/A = 0.5,
For clay, k/A = 0.25.
Q = 0.0059 m^3/sec,
Q = 0.0059 * 60 * 60 m^3/hour,
A = (pi/4) * d^2.
GANESH MAHALE said:
9 years ago
Depression head calculation from formula Q = K H Where k = 1 for course grain soil, 0.5 for fine sand and 0.25 for clay.
For this case, k =1 thus, Q=3.
For this case, k =1 thus, Q=3.
Laxmipriya dhal said:
9 years ago
@Sahil, What is the value of k?
Vijay said:
9 years ago
Please give the clear solution of this problem.
Sahil Upadhyay GGMU said:
9 years ago
This can be solved by:
Q = (K/A).A.H.
Q = (K/A).A.H.
Mdpawar said:
10 years ago
How to solve this problem?
Manoj said:
1 decade ago
What is formula?
Deepli said:
1 decade ago
Please solve this problem.
Punati said:
1 decade ago
Could you please explain me to solve this problem?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers