Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 4 (Q.No. 6)
6.
If the average daily demand of a city of 50, 000 population, is 20 m.l.d., the maximum daily demand is
Discussion:
16 comments Page 1 of 2.
Joe said:
5 years ago
Max daily demand = 1.8 * avg daily demand.
Max hourly demand= 1.5* max daily demand.
Max hourly demand= 2.7 *avg daily demand.
Max hourly demand= 1.5* max daily demand.
Max hourly demand= 2.7 *avg daily demand.
(19)
Anant said:
6 years ago
Max daily demand 1.8.
Max monthly demand 1.4.
Max hourly demand 1.5.
Max monthly demand 1.4.
Max hourly demand 1.5.
(2)
Ayaz said:
1 decade ago
Max daily demand = 1.8 avg daily demand.
= 1.8*20.
= 36.
= 1.8*20.
= 36.
(1)
Shubhangi borse said:
7 years ago
1.8 from where it get?
(1)
JD Panwar said:
4 years ago
Max daily demand 1.8.
(1)
John mark said:
9 years ago
@Ayaz.
Where did you get 1.8?
Where did you get 1.8?
Abhishek said:
7 years ago
1.8 is daily variation factor.
VikRam Syal said:
7 years ago
What we can also take 3.0 because pop is 50, 000 so final answer. According to me 60 is correct.
Naveed ullah said:
7 years ago
M.l.d stand for? Please explain.
Nikhil said:
7 years ago
@Naveed Ullah.
Million Litres Per Day.
Million Litres Per Day.
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