Civil Engineering - Water Supply Engineering - Discussion

6. 

If the average daily demand of a city of 50, 000 population, is 20 m.l.d., the maximum daily demand is

[A]. 24 mld
[B]. 30 mld
[C]. 36 mld
[D]. 54 mld.

Answer: Option C

Explanation:

No answer description available for this question.

Ayaz said: (Oct 9, 2013)  
Max daily demand = 1.8 avg daily demand.

= 1.8*20.

= 36.

John Mark said: (Jun 3, 2016)  
@Ayaz.

Where did you get 1.8?

Shubhangi Borse said: (Nov 5, 2017)  
1.8 from where it get?

Abhishek said: (Nov 21, 2017)  
1.8 is daily variation factor.

Vikram Syal said: (Feb 4, 2018)  
What we can also take 3.0 because pop is 50, 000 so final answer. According to me 60 is correct.

Naveed Ullah said: (Mar 18, 2018)  
M.l.d stand for? Please explain.

Nikhil said: (May 24, 2018)  
@Naveed Ullah.

Million Litres Per Day.

Sam said: (Jun 1, 2019)  
Isn't it 1.5 avg daily demand?

Shaz said: (Jul 15, 2019)  
Yes, its 1.5. Right @Sam.

Ibrar said: (Sep 10, 2019)  
What is fire demand of a 50000 population with and the average consumption of 200 litre per/capita/day and floor area of 600 m2 and a height of 4 stories?

Please, someone, help me to solve it.

Anant said: (Sep 22, 2019)  
Max daily demand 1.8.
Max monthly demand 1.4.
Max hourly demand 1.5.

Apeksha said: (Oct 19, 2019)  
Thank you @Anant.

Joe said: (Jan 24, 2020)  
Max daily demand = 1.8 * avg daily demand.
Max hourly demand= 1.5* max daily demand.
Max hourly demand= 2.7 *avg daily demand.

Sueaj said: (Jun 6, 2020)  
36 mld is the correct answer.

Jd Panwar said: (Jun 27, 2021)  
Max daily demand 1.8.

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