Civil Engineering - Water Resources Engineering - Discussion
Discussion Forum : Water Resources Engineering - Section 1 (Q.No. 43)
43.
A well penetrates to 30 m below the static water table. After 24 hours of pumping at 31.40 litres/minute, the water level in a test well at a distance of 80 m is lowered by 0.5 m and in a well 20 m away water is lowered by 1.0 m. The transmissibility of the auifer, is
Discussion:
14 comments Page 1 of 2.
Kaushik das said:
1 decade ago
Please explain.
Deepak said:
10 years ago
Please explain, how it comes?
Swati said:
9 years ago
Explain it please.
Srinu said:
9 years ago
Apply formula.
q = 2piBK(S2 - S1)/ln(r2/r1).
q = 2piBK(S2 - S1)/ln(r2/r1).
Srinu said:
9 years ago
Transmissibility T = BK.
M. A Sidi said:
9 years ago
By Thiem's formula.
Q = (2 * 3.142 * T(s1 - s2))/(2.3 * log(r2/r1)).
By making T the subject and substituting the given parameters we have T = -1.384.
Q = (2 * 3.142 * T(s1 - s2))/(2.3 * log(r2/r1)).
By making T the subject and substituting the given parameters we have T = -1.384.
Matiur Rahaman said:
9 years ago
Q = 31.40lit/min = 31.40/60 * 1000 = 0.000523mitre cube per second.
Where
K = 0.000523 * 2.3 * log(80/20)/3.14 * (29.5 * 29.5-29 * 29).
=0.00000788 miter per second.
T = kb = 0.00000788 * 30.
= 0.000236 meter square per second.
=1.385 meter square per minute.
Where
K = 0.000523 * 2.3 * log(80/20)/3.14 * (29.5 * 29.5-29 * 29).
=0.00000788 miter per second.
T = kb = 0.00000788 * 30.
= 0.000236 meter square per second.
=1.385 meter square per minute.
Mahesh said:
8 years ago
29.5*29.5 - 29*29 how it will came?
Saranya said:
8 years ago
@Mahesh.
Here,
30-0.5= 29.5,
30-1=29.
Here,
30-0.5= 29.5,
30-1=29.
Pihu said:
7 years ago
@Matiur.
After m2/s to m2/min answer not comes.
Please explain it in detail.
After m2/s to m2/min answer not comes.
Please explain it in detail.
(1)
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