### Discussion :: Water Resources Engineering - Section 1 (Q.No.43)

Kaushik Das said: (Jan 27, 2015) | |

Please explain. |

Deepak said: (Jan 29, 2016) | |

Please explain, how it comes? |

Swati said: (Aug 8, 2016) | |

Explain it please. |

Srinu said: (Oct 14, 2016) | |

Apply formula. q = 2piBK(S2 - S1)/ln(r2/r1). |

Srinu said: (Oct 14, 2016) | |

Transmissibility T = BK. |

M. A Sidi said: (Oct 15, 2016) | |

By Thiem's formula. Q = (2 * 3.142 * T(s1 - s2))/(2.3 * log(r2/r1)). By making T the subject and substituting the given parameters we have T = -1.384. |

Matiur Rahaman said: (Jan 14, 2017) | |

Q = 31.40lit/min = 31.40/60 * 1000 = 0.000523mitre cube per second. Where K = 0.000523 * 2.3 * log(80/20)/3.14 * (29.5 * 29.5-29 * 29). =0.00000788 miter per second. T = kb = 0.00000788 * 30. = 0.000236 meter square per second. =1.385 meter square per minute. |

Mahesh said: (Nov 4, 2017) | |

29.5*29.5 - 29*29 how it will came? |

Saranya said: (Dec 7, 2017) | |

@Mahesh. Here, 30-0.5= 29.5, 30-1=29. |

Pihu said: (Apr 10, 2018) | |

@Matiur. After m2/s to m2/min answer not comes. Please explain it in detail. |

Hagos said: (Aug 27, 2018) | |

Q=2π T(s1_s2)/2.3log(r2/r1), Where Q=31.40,S1=1,S2=0.5,r2=80,r1=20. Therefore substitute it then T=1.385. |

Amrit Gajendra said: (Nov 17, 2018) | |

The discharge should be taken in S.I. unit and the answer will come as 0.01385. |

Anim said: (Aug 22, 2019) | |

Thanks @Matiur Rahaman. |

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