Civil Engineering - Water Resources Engineering - Discussion
Discussion Forum : Water Resources Engineering - Section 2 (Q.No. 23)
23.
If the velocities of flow of a stream of 10 m depth recorded by a current meter at depths of 2 m and 8 m are 0.7 m and 0.3 m respectively, the discharge per unit width of the stream in cubic metres, is
Discussion:
16 comments Page 1 of 2.
Kawsar said:
5 years ago
Thanks all for explaining.
Karan said:
6 years ago
Thanks @Rashmi.
Khattak said:
6 years ago
Thanks for solving @Waqar.
Anomis said:
7 years ago
Taking average velocity=0.7+0.3/2=0.5m/s.
Now,
We know that,
Q=Area x velocity,
Here velocity= average velocity =0.5m/s,
Area = depth x breadth of channel,
Taking width as b=1m.
Area= 10 x 1=10metre square.
Now Discharge=10 x 0.5=5 cubic metre/sec.
We know that discharge intensity or discharge per unit width = Q/b =5/1= 5.
Now,
We know that,
Q=Area x velocity,
Here velocity= average velocity =0.5m/s,
Area = depth x breadth of channel,
Taking width as b=1m.
Area= 10 x 1=10metre square.
Now Discharge=10 x 0.5=5 cubic metre/sec.
We know that discharge intensity or discharge per unit width = Q/b =5/1= 5.
(3)
Akshay said:
7 years ago
Q=A*V.
We know that;
velocity @ depth 2m = 0.7m/s and,
@ depth 8m = 0.3m/s.
discharge
@ depth 2m, Q=A*V.
=(10*1)*0.7 A=L*B=10*1(UNIT WIDTH),
=7 mt cube/sec.
At depth 8m, Q=A*V.
=(10*1)*0.3 A=L*B=10*1(UNIT WIDTH),
=3 mt cube/sec.
Average of Q=7+3/2,
=10/2,
=5 mt cube/sec.
We know that;
velocity @ depth 2m = 0.7m/s and,
@ depth 8m = 0.3m/s.
discharge
@ depth 2m, Q=A*V.
=(10*1)*0.7 A=L*B=10*1(UNIT WIDTH),
=7 mt cube/sec.
At depth 8m, Q=A*V.
=(10*1)*0.3 A=L*B=10*1(UNIT WIDTH),
=3 mt cube/sec.
Average of Q=7+3/2,
=10/2,
=5 mt cube/sec.
(3)
Keshav said:
7 years ago
Taking average velocity=0.7+0.3/2=0.5m/s.
Now,
We know that,
Q=Area x velocity,
Here velocity= average velocity =0.5m/s,
Area = depth x breadth of channel,
Taking width as b=1m.
Area= 10 x 1=10metre square.
Now Discharge=10 x 0.5=5 cubic metre/sec.
We know that discharge intensity or discharge per unit width =Q/b =5/1= 5.
Now,
We know that,
Q=Area x velocity,
Here velocity= average velocity =0.5m/s,
Area = depth x breadth of channel,
Taking width as b=1m.
Area= 10 x 1=10metre square.
Now Discharge=10 x 0.5=5 cubic metre/sec.
We know that discharge intensity or discharge per unit width =Q/b =5/1= 5.
(2)
Priya said:
7 years ago
Thanks a lot @Waqar.
Raj said:
7 years ago
Thanks @Waqar.
Ashish said:
8 years ago
Thanks @Waqar.
Waqar ahmed awan said:
8 years ago
Velocities by current meter=0.7 and 0.3m.
Taking average velocity=0.7+0.3/2=0.5m/s.
Now,
We know that,
Q=Area x velocity,
Here velocity= average velocity =0.5m/s,
Area = depth x breadth of channel,
Taking width as b=1m.
Area= 10 x 1=10metre square.
Now Discharge=10 x 0.5=5 cubic metre/sec.
We know that discharge intensity or discharge per unit width =Q/b =5/1= 5ans.
Hope helped.
Taking average velocity=0.7+0.3/2=0.5m/s.
Now,
We know that,
Q=Area x velocity,
Here velocity= average velocity =0.5m/s,
Area = depth x breadth of channel,
Taking width as b=1m.
Area= 10 x 1=10metre square.
Now Discharge=10 x 0.5=5 cubic metre/sec.
We know that discharge intensity or discharge per unit width =Q/b =5/1= 5ans.
Hope helped.
(3)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers