Civil Engineering - Water Resources Engineering - Discussion

Discussion :: Water Resources Engineering - Section 1 (Q.No.28)

28.

If y is the depth of water at any section, then the mean velocity is

 [A]. 0.1 y [B]. 0.2 y [C]. 0.3 y [D]. 0.5 y [E]. 0.6 y.

Explanation:

No answer description available for this question.

 Pratap Baral said: (Oct 20, 2014) Why not 0.5 y?

 Uma said: (Feb 7, 2015) How its 0.6Y?

 Suman Debnath said: (Jun 18, 2015) Can you explain how its becomes 0.6y?

 Raman said: (Oct 6, 2015) See the channel section with velocity distribution.

 Chandu said: (Nov 21, 2016) Due to surface currents max velocity does not occur at surface max velocity occurs at 0.25y Mean velocity at V 0.6y = (V 0.8y+V 0.6y)/2.

 Gayatri said: (Jun 25, 2017) Please, explain anyone?

 Zee said: (Aug 2, 2017) How it is? Explain.

 Dvs said: (Aug 19, 2017) Yes, you are correct @Chandu.

 Krunal said: (Mar 2, 2018) max. velocity occur at depth 0.05y to 0.15y below free surface. mean velocity occur at an average of the velocities measured at 0.2y and 0.8y depth from the free surface. So, the answer is nearly from 0.6y to 0.7y.

 Chandu said: (Mar 23, 2018) For natural streams 0.6y. For floods 0.5y.

 Jaykantariya said: (May 21, 2019) Normal Indian practise is to measure the velocity at 0.6 depth and take it as the mean velocity. Mean velocity = 1/10(Vs +2V*0.2+2V*0.4+2V*0.6+2V*0.8+Vbottom).

 Gadisa said: (Aug 6, 2019) Can you explain how its become 0.6y? Please explain it clearly.

 Ansh Mishra said: (Sep 2, 2020) Not getting the solution. Anyone explain it in detail.