Civil Engineering - Waste Water Engineering - Discussion

Discussion Forum : Waste Water Engineering - Section 7 (Q.No. 10)
10.
If a 2% solution of sewage sample is incubated for 5 days at 20°C and the dissolved oxygen depletion was found to be 8 mg/l. The BOD of the sewage is
100 mg/l
200 mg/l
300 mg/l
400 mg/l.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Anuj said:   6 years ago
BOD = Loss of DO * dilution factor.
Dilution factor = total sample / vol of sewage.
= 8 * 100/2.
= 400.

Debasis palui said:   3 years ago
BOD = Loss of DO * dilution factor.
Dilution factor = total sample / vol of sewage.
= 8 * 100/2.
= 400.

Bharath said:   9 years ago
BOD = loss of oxygen / % diluted = 8/0.02 =400mg/l.

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