Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 7 (Q.No. 10)
10.
If a 2% solution of sewage sample is incubated for 5 days at 20°C and the dissolved oxygen depletion was found to be 8 mg/l. The BOD of the sewage is
Discussion:
3 comments Page 1 of 1.
Bharath said:
1 decade ago
BOD = loss of oxygen / % diluted = 8/0.02 =400mg/l.
Anuj said:
8 years ago
BOD = Loss of DO * dilution factor.
Dilution factor = total sample / vol of sewage.
= 8 * 100/2.
= 400.
Dilution factor = total sample / vol of sewage.
= 8 * 100/2.
= 400.
Debasis palui said:
5 years ago
BOD = Loss of DO * dilution factor.
Dilution factor = total sample / vol of sewage.
= 8 * 100/2.
= 400.
Dilution factor = total sample / vol of sewage.
= 8 * 100/2.
= 400.
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