Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 5 (Q.No. 41)
41.
The settlement velocity of a solid (diameter 0.5 mm, specific gravity 1.75) in water having temperature 10°C, is
Discussion:
10 comments Page 1 of 1.
Anirban Roy said:
5 years ago
Here unit is also incorrect. It should be mm/sec. If cm/sec then answer shall be 31.35 cm/sec as per Shweta's formula
Shweta said:
5 years ago
@Rathi formula is wrong.
V = 418*(G-1)D((3T+70)/100)
Here,
specific gravity G=2.5.
the diameter of particle D=0.5mm.
temperature T=10.
Answer is 313.5cm/sec.
V = 418*(G-1)D((3T+70)/100)
Here,
specific gravity G=2.5.
the diameter of particle D=0.5mm.
temperature T=10.
Answer is 313.5cm/sec.
(2)
Raj said:
7 years ago
Thank you all for giving the solution in detail.
(2)
Gopal said:
7 years ago
Here, Specific gravity is 2.5 then we get correct answer with formula 418(Gs-Gw)d(3T+70/100).
(1)
Priya said:
7 years ago
Yes, correct @Rathi.
No, d in the formula. So the answer is 313.5cm/sec.
No, d in the formula. So the answer is 313.5cm/sec.
Baba said:
7 years ago
The ans is 15.675 cm/sec.
D=0.5mm=0.05cm.
D=0.5mm=0.05cm.
(1)
Abhishek said:
8 years ago
Yes, @Shwetha.
Ans is 156.75cm/sec.
418*(1.75-1)*0.5*((3*10+70)/100)=156.75cm/sec. Because if D=0.1mm to 1mm, V=418*(S-1)*D*((3T+70)/100).
Ans is 156.75cm/sec.
418*(1.75-1)*0.5*((3*10+70)/100)=156.75cm/sec. Because if D=0.1mm to 1mm, V=418*(S-1)*D*((3T+70)/100).
Shwetha said:
8 years ago
We should consider diameter in that formula right ?
V = 418*(S-1)D((3T+70)/100).
V = 418*(S-1)D((3T+70)/100).
(1)
Vaijanath Patil said:
8 years ago
Thanks @Rathi.
Rathi said:
9 years ago
If Diameter of the particle lies between 0.1mm to 1mm then settling is called transition settling is given by,
V = 418*(S-1)((3T+70)/100).
V = 418*(1.75-1)((3*10+70)/100).
V = 313.5 cm/sec.
V = 418*(S-1)((3T+70)/100).
V = 418*(1.75-1)((3*10+70)/100).
V = 313.5 cm/sec.
(1)
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