Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 33)
33.
If the side of a square sewer is 1000 mm, the diameter of a hydraulically equivalent circular section, is
Discussion:
16 comments Page 1 of 2.
Nabam jenny said:
2 years ago
Please solve this problem in detail to understand.
Mahant said:
4 years ago
D =1.09B,
For egg shaped sewer, D'= 0.84 D.
For egg shaped sewer, D'= 0.84 D.
(1)
Jay said:
5 years ago
@Gugu.
Use Mannings formula for velocity and multiply with Area to find discharge. Hydraulic equivalent means having the same discharge. So equate discharge from both square and a circular section. You will get your answer.
Use Mannings formula for velocity and multiply with Area to find discharge. Hydraulic equivalent means having the same discharge. So equate discharge from both square and a circular section. You will get your answer.
Rishish saxena said:
6 years ago
The ratio of the dia of a circular section and the side of a square section hydraulically equivalent is 1.095.
(2)
Gugu said:
7 years ago
@Dhanu.
How 1.094?
How 1.094?
Priya said:
8 years ago
Thanks @Dhanu.
Abhishek said:
8 years ago
D=1.1B.
It is the relation between circular and square sewer.
It is the relation between circular and square sewer.
Dhanu said:
8 years ago
d=1.094b.
b=side of square.
d=dia of crcular section.
D=1.094 * 1000 = 1094.
b=side of square.
d=dia of crcular section.
D=1.094 * 1000 = 1094.
(3)
Zahir shah said:
8 years ago
Relation between square and circular sewer :-
π * D^(8/3) = 4 * b^(8/3)
D^(8/3) = 4 * b^(8/3)
D^(8/3) = 4 * 1000^(8/3)/ 3.14
D^(8/3) = 127323954.47
Or D = 127323954.47^(3/8)
So D = 1094.82 say 1095.
π * D^(8/3) = 4 * b^(8/3)
D^(8/3) = 4 * b^(8/3)
D^(8/3) = 4 * 1000^(8/3)/ 3.14
D^(8/3) = 127323954.47
Or D = 127323954.47^(3/8)
So D = 1094.82 say 1095.
(4)
Sourav said:
8 years ago
@Lakshmi then 1000^2= πD^2/4.
Then D=1128.
Then D=1128.
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