Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 2 (Q.No. 13)
13.
If the depth of partial flow in a sewer of diameter 2 m, is 50 cm, its wetted perimeter is
π
Discussion:
12 comments Page 1 of 2.
JOTIBRATA said:
4 years ago
Thanks all for explaining.
Junaid marwat said:
5 years ago
If the pipe is neither full nor half then the formula for wetted perimeter is
p= 2 * cos(r-h/r).
As d=2 so r=1 & h=50cm=0.5m,
2 *cos(1-0.5/1).
p=1.99 almost equal to 2 and 2π/3 = 2.0.
Thus the answer will be 2π/3.
p= 2 * cos(r-h/r).
As d=2 so r=1 & h=50cm=0.5m,
2 *cos(1-0.5/1).
p=1.99 almost equal to 2 and 2π/3 = 2.0.
Thus the answer will be 2π/3.
(2)
Pankaj dubey said:
6 years ago
d/D = 0.5(1-cosθ/2).
θ = 120.
p/P=θ/360,
P=πD.
p = 2π/3.
θ = 120.
p/P=θ/360,
P=πD.
p = 2π/3.
Umesh said:
6 years ago
Thanks @Nitai.
Nitai Maity said:
7 years ago
Depth(h)=D/2(1-cos a/2),where a is central angle.
Data given that h=50 cm=500 mm & D=2m=2000 mm,
so,500=2000/2(1-cos a/2),
or,cos a/2=1/2,
or,cos a/2=cos 60,
or,a/2=60 degree,
or,a=120 degree.
Again we know that wetted perimeter(p)= πD .a/360.
p=π x 2 x120/ 360=2π /3.
Data given that h=50 cm=500 mm & D=2m=2000 mm,
so,500=2000/2(1-cos a/2),
or,cos a/2=1/2,
or,cos a/2=cos 60,
or,a/2=60 degree,
or,a=120 degree.
Again we know that wetted perimeter(p)= πD .a/360.
p=π x 2 x120/ 360=2π /3.
(1)
Ranjitha said:
8 years ago
Wetted perimeter formula = p = cos-1 ( 1 - ( h / r ) ) * D.
here h= 50 cm=0.5m.
D=2m, r= 1m.
=cos-1(1-(0.5/1))= cos-1(0.5)=60 degree.
=60x0.01745 rad = 1.0472 rad.
p= 1.0472*2 = 2.0944.
From the given answers,
2π/3 = 2.0933.
So the answer is 2π/3.
here h= 50 cm=0.5m.
D=2m, r= 1m.
=cos-1(1-(0.5/1))= cos-1(0.5)=60 degree.
=60x0.01745 rad = 1.0472 rad.
p= 1.0472*2 = 2.0944.
From the given answers,
2π/3 = 2.0933.
So the answer is 2π/3.
Tridib said:
9 years ago
A-central angle.
Shilpa said:
9 years ago
@Premkumar.
What is 'a' in that formula?
What is 'a' in that formula?
Premkumar said:
9 years ago
Diameter of partially filled with fluid.
D = (D*(1-cos (a/2))/2.
Where D = Original dia.
D = (D*(1-cos (a/2))/2.
Where D = Original dia.
Rakesh said:
9 years ago
How, I didn't get?
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