Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 3 (Q.No. 35)
35.
The density of population over 40 hectares is 250/hectare. If water supply demand per day is 200 litres and sewage discharge is 80% of water supply, the sewage flow in sewers of separate system, is
Discussion:
18 comments Page 1 of 2.
Shruthi said:
10 years ago
Please explain.
Samm said:
9 years ago
Answer should be 0.0185 cumec.
Explanation =[(40 * 250) * 200 * 80%/(1000 * 24 * 60 * 60)] cumec.
Am I right?
Explanation =[(40 * 250) * 200 * 80%/(1000 * 24 * 60 * 60)] cumec.
Am I right?
Mukesh maurya said:
9 years ago
@Samm.
How you take 1000 in the denominator?
How you take 1000 in the denominator?
(1)
Hemm said:
9 years ago
Yes, it should be 0.0185 cumec.
Rocky said:
9 years ago
Yes, I also get 0.0185 cumec.
Rajat said:
9 years ago
@Samm, How did you take 1000 in the denominator?
Saunak said:
9 years ago
@Rajat.
He converted litre into cumec.
He converted litre into cumec.
Anand kumar said:
9 years ago
Dry weather flow is equal to 3 times of average flow. So the answer is 0.185 * 3 i.e 0.05556.
Niranjan said:
9 years ago
Great section, thanks to all.
(1)
Chayya said:
8 years ago
Yes, right @Anand.
3 is a safety factor in a sewer.
3 is a safety factor in a sewer.
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