Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 29)
29.
A pin-jointed tower truss is loaded as shown in the given figure. The force induced in the member DF is
1.5 kN (tension)
4.5 kN (tension)
1.5 kN (compression)
4.5 kN (compression)
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Roland said:   1 decade ago
Answer is D,

Member AD is in compression hence at joint D the vertical component of member AD will be balanced by member DF (compression).

Francis said:   1 decade ago
Yes, it must be compression but I think it would only be 1.5kN.

Hrisikesh sil said:   10 years ago
It should be in compression.

Daman sharma said:   9 years ago
It must be 1.5 compressions. So the answer should be (c).

Chintu said:   8 years ago
Taking moment about E we will get reaction at F as 4.5 upwards and hence 4.5 kN comp force in member DF.

Immu azm said:   8 years ago
Answer is D.

Reaction Re=4.5 downward now apply zero force member rule force in member EF =0 ( force CE in member AND reaction at E are collinear force in non collinear member must be zero ).

Now cut the member X-X passing through CA,CD,FD. NOW TAKE moment about C we will get 4.5 * 4 = DF * 4.

Immu azm said:   8 years ago
Reaction at E 4.5 downward and at F 4.5 upwards.

Maxp50 said:   8 years ago
Ans is C.

Calculate reactions now go with the method of section cutting member EF CF DF.

Now, do summation Fx=0 and Fy=0.

Force in DF=-1.5KN i.e. compression.

Mike Edrad said:   8 years ago
1.5 KN Compression because it is towards the joint.

Bharti Sharma said:   7 years ago
1.5 KN Compression.

Calculate horizontal and vertical reactions and then by the method of sections, take equilibrium of horizontal, vertical forces and moments.


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