Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 29)
29.
A pin-jointed tower truss is loaded as shown in the given figure. The force induced in the member DF is
Discussion:
14 comments Page 2 of 2.
Sharma said:
7 years ago
1.5 Tension.
The reaction at F will be 4.5 upward.
And taking vertical equilibrium we have;
3/5 FC - FD = 4.5.
Now, the force in FC will be compressive only and subtracting force FD is equal to reaction 4.5 which means force FD and reaction is in same direction i.e upward which means the force FD is a Tension force
The reaction at F will be 4.5 upward.
And taking vertical equilibrium we have;
3/5 FC - FD = 4.5.
Now, the force in FC will be compressive only and subtracting force FD is equal to reaction 4.5 which means force FD and reaction is in same direction i.e upward which means the force FD is a Tension force
Arashdeep Singh said:
7 years ago
Take a section from mid of CE to mid of DF and calculate moment about joint C.
Then, You will get a compressive force of 1.5 kN.
Then, You will get a compressive force of 1.5 kN.
CIVi said:
4 years ago
The answer is correct.
taking reaction about F.
4xE= (2 x 3) + (2 x 6)
E = 18/4.
E = 4.5 (compression).
taking reaction about F.
4xE= (2 x 3) + (2 x 6)
E = 18/4.
E = 4.5 (compression).
Dhritiman said:
2 years ago
Force at member DF = (2*3)/4 = 1.5 Tension.
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