Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 3 (Q.No. 28)
28.
Following data are given for two soil samples A and B :
Sample A : Void ratio = 1, total volume = 1 m3
Sample B : Void ratio = 2, total volume = 1 m3.
The two samples are mixed and compacted in a mould to a volume of 1 m3. Which one of the following figures correctly indicates the porosity of the compacted soil ?
17%
54%
60%
83%
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Faisal Moiz said:   6 years ago
Vs(total) = Vs1 + Vs2.

1/1+e = (1/1+1) + (1/1+2).
1/1+e = 1/2 + 1/3,
1/1+e = .5+.33,
1/1+e = .83,
1+e = 1/.83 (cross multiplication).
1+e = 1.2,
e = .2,
n = e/1+e,
n = .2/1.2,
n = .17,
So in percent .17x100 = 17%.
(12)

Bishal said:   4 years ago
@Faisal,

How u wrote Vs=1/1+e?

Can you please elaborate?
(3)

Deepak said:   6 years ago
Here Vs = Vtotal/(1+e).
(2)

Dolly said:   7 years ago
How you get Vs?
(1)

Bishal said:   4 years ago
How you write Vs = Vtotal/(1+e)?

Please elaborate it.
(1)

MAYANK said:   10 years ago
Correct answer should be 20%.

Saksham said:   10 years ago
How? Can you give solution please?

Mayank said:   9 years ago
Vs in 1st sample = .5V.
Vs in 2nd sample = .33V.

Vv = V - Vs = 1 -(.5 + .33).
Thus n = Vv/V = .166.

Chhaya said:   8 years ago
Thanks @ Mayank.

Mukesh ranjan said:   8 years ago
@Mayank.

Vv = 1 - 0.83 = 0.17
n = Vv/V.
n = 0.17/1 as V is given 1.
So correct answer is 17%.


Post your comments here:

Your comments will be displayed after verification.