Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 9 (Q.No. 42)
42.
In the network given in figure, the maximum number of shovels and dumpers required are
Discussion:
2 comments Page 1 of 1.
Uttam said:
7 years ago
Can anybody explain about this?
Rajat thapliyal said:
4 years ago
Activity 1-2 and 1-3 are parallel activity and run parallel for 2 days as the duration for 1-2 is 2 days so for this time no of shovel required =1+3=4.
And no of dumper reqd =4+8=12.
Now, activities 1-2 finish after 3 days and 1-3 continue with 2-3 and 2-4 for the remaining 2 days.
So no of shovel reqd=3+4+3=10.
No dumper required =8+4+12=24.
After 1-3 is complete activity 2-3 and 2-4 runs for 2 days as after 2 days activity 2-3 will finish.
So, no of shovel reqd= 4+3=7.
No of dumper reqd=4+12=16.
In a similar manner requirement of shovel and dumper can be computed for remaining activities.
Thanks.
And no of dumper reqd =4+8=12.
Now, activities 1-2 finish after 3 days and 1-3 continue with 2-3 and 2-4 for the remaining 2 days.
So no of shovel reqd=3+4+3=10.
No dumper required =8+4+12=24.
After 1-3 is complete activity 2-3 and 2-4 runs for 2 days as after 2 days activity 2-3 will finish.
So, no of shovel reqd= 4+3=7.
No of dumper reqd=4+12=16.
In a similar manner requirement of shovel and dumper can be computed for remaining activities.
Thanks.
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