Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 4 (Q.No. 22)
22.
A machine costs Rs. 16, 000. By constant rate of declining balance method of depreciation, its salvage value after an expected life of 3 years is Rs. 2, 000. The rate of depreciation is
Discussion:
5 comments Page 1 of 1.
Navi said:
8 years ago
16000(1-r)^3 = 2000.
Sadashiva said:
8 years ago
Rate of depreciation=(1- C's/Ci)^1/n.
= ( 1-16000/2000)^1/3
= 0.5.
= ( 1-16000/2000)^1/3
= 0.5.
Omer said:
7 years ago
Subtract Rs.2000.
Rs 16000- Rs 2000 = Rs 14000.
Convert years to hours 3 year = 26280hours.
The rate of depreciation = 14000/26280 = .53.
Rs 16000- Rs 2000 = Rs 14000.
Convert years to hours 3 year = 26280hours.
The rate of depreciation = 14000/26280 = .53.
Akhil said:
5 years ago
1-(2000/16000)^1/3.
= 0.5.
= 0.5.
(1)
Rahul verma said:
2 years ago
According to decline balance method,
rate of depreciation P=1-(s/c)^1/n.
P = 1-(2000/16000)^1/3,
P = 1-(1/8)^1/3,
P = 1-1/2,
P = 0.5.
rate of depreciation P=1-(s/c)^1/n.
P = 1-(2000/16000)^1/3,
P = 1-(1/8)^1/3,
P = 1-1/2,
P = 0.5.
(3)
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