Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 27 (Q.No. 7)
7.
If a circular shaft is subjected to a torque T and a bending moment 'M' the ratio of the maximum shear stress to the maximum bending stress is given by :
Discussion:
6 comments Page 1 of 1.
Viney bhatia said:
4 years ago
Max shear stress to max Bending stress: T/2M.
In case Max Bending Stress to Max Shear stress : 2M/T.
In case Max Bending Stress to Max Shear stress : 2M/T.
(1)
PRASHANT said:
8 years ago
Can anyone explain it? please.
DARSHAN said:
8 years ago
Max shear stress = 16T/πd^3.
Bending stress = 32M/πd^3.
so when you divide 16T/32M = T/2M.
Bending stress = 32M/πd^3.
so when you divide 16T/32M = T/2M.
Anju Philip said:
7 years ago
Maximum shear stress is 1.2N/mm2. Maximum longitudinal stress is 12N/mm2.
The span to depth ratio is? Anybody, please help me.
The span to depth ratio is? Anybody, please help me.
Mohit said:
6 years ago
What it would be for rectangular cross sections?
Prabhat said:
6 years ago
@Darshan's explanation is right.
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