Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 2 (Q.No. 20)
20.
The plastic section modulus of a rectangular section of width 100 mm and depth 12 mm is
1000 mm3
1800 mm3
2400 mm3
3600 mm3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Deepak Dalal and Ritu Dalal said:   8 years ago
Section modulus = moment of inertia of the area / maximum distance of any point from the axis.
Moment of inertia for rectangular section = bh^3/12.
Maximum distance of any point from the axis = h/2.
So, section modulus for rectangular section = bh^2/6.

And the correct answer from above from is 2400.
(1)

Anil kumar said:   6 years ago
(Zp=Ac x yc+At x yt).
Ac = area of compression zone.
At = area of tension zone.
Yc &yt are the C.G of the both zones.

So the answer is zp = 600x300+600x300.
=3600.

Darshan said:   8 years ago
Plastic modulus and elastic modulus are different.
shape factor comes into picture here;
so 2400 *1.5 = 3600.
shape factor is 1.5 for rectangular section.

Kanu said:   8 years ago
Here the section is rectangular.

Z= (bd^2)/4 is right
If in case there is a circular section then section modulus will be;
Z = (bd^2)/6.
(1)

Subha Annadurai said:   7 years ago
For rectangle,
Plastic section modules = bd^2/4,
Elastic section modules = bd^2/6,
Shape factor = 1.5.
(3)

Naveen Kallan said:   8 years ago
Shape factor= 1.5 for rectangular section
S.F = Zp/Ze
Ze = bd^2/6
Zp = 3600 mm^3.

Subha Annadurai said:   7 years ago
How to find plastic section modules & elastic section modules for rectangle?

Aatif said:   8 years ago
Answer should be 2400. Section modulus for rect section- bd^2/6.

Ravi Rajput said:   7 years ago
How to calculate plastic section modulus? Please explain.

Barqat sheikh said:   1 decade ago
Plastic section modulus = b*h^2/4.

= 3600 mm^3.


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