Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 2 (Q.No. 20)
20.
The plastic section modulus of a rectangular section of width 100 mm and depth 12 mm is
Discussion:
11 comments Page 1 of 2.
Anil kumar said:
6 years ago
(Zp=Ac x yc+At x yt).
Ac = area of compression zone.
At = area of tension zone.
Yc &yt are the C.G of the both zones.
So the answer is zp = 600x300+600x300.
=3600.
Ac = area of compression zone.
At = area of tension zone.
Yc &yt are the C.G of the both zones.
So the answer is zp = 600x300+600x300.
=3600.
Ravi Rajput said:
7 years ago
How to calculate plastic section modulus? Please explain.
Subha Annadurai said:
7 years ago
For rectangle,
Plastic section modules = bd^2/4,
Elastic section modules = bd^2/6,
Shape factor = 1.5.
Plastic section modules = bd^2/4,
Elastic section modules = bd^2/6,
Shape factor = 1.5.
(3)
Subha Annadurai said:
7 years ago
How to find plastic section modules & elastic section modules for rectangle?
Darshan said:
8 years ago
Plastic modulus and elastic modulus are different.
shape factor comes into picture here;
so 2400 *1.5 = 3600.
shape factor is 1.5 for rectangular section.
shape factor comes into picture here;
so 2400 *1.5 = 3600.
shape factor is 1.5 for rectangular section.
Aatif said:
8 years ago
Answer should be 2400. Section modulus for rect section- bd^2/6.
Naveen Kallan said:
8 years ago
Shape factor= 1.5 for rectangular section
S.F = Zp/Ze
Ze = bd^2/6
Zp = 3600 mm^3.
S.F = Zp/Ze
Ze = bd^2/6
Zp = 3600 mm^3.
Deepak Dalal and Ritu Dalal said:
8 years ago
Section modulus = moment of inertia of the area / maximum distance of any point from the axis.
Moment of inertia for rectangular section = bh^3/12.
Maximum distance of any point from the axis = h/2.
So, section modulus for rectangular section = bh^2/6.
And the correct answer from above from is 2400.
Moment of inertia for rectangular section = bh^3/12.
Maximum distance of any point from the axis = h/2.
So, section modulus for rectangular section = bh^2/6.
And the correct answer from above from is 2400.
(1)
Kanu said:
8 years ago
Here the section is rectangular.
Z= (bd^2)/4 is right
If in case there is a circular section then section modulus will be;
Z = (bd^2)/6.
Z= (bd^2)/4 is right
If in case there is a circular section then section modulus will be;
Z = (bd^2)/6.
(1)
Hemanth kumar said:
9 years ago
Z = bd^2/6 = 2400mm^3.
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