Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 16 (Q.No. 37)
37.
A bullet of mass 0.01 kg moving with a velocity of 401 m/s strikes a block of mass 4 kg which is free to move in the direction of the bullet, and gets embedded in it. The overall loss of kinetic energy is
Discussion:
1 comments Page 1 of 1.
Arul said:
8 years ago
Here, v2=0.01*401/(0.01+4)=1 then loss of kinetic energy=0.5*0.01*(401^2-1^2)=804.
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