Civil Engineering - UPSC Civil Service Exam Questions - Discussion


A bullet of mass 0.01 kg moving with a velocity of 401 m/s strikes a block of mass 4 kg which is free to move in the direction of the bullet, and gets embedded in it. The overall loss of kinetic energy is

[A]. 80.2 Nm
[B]. 401 Nm
[C]. 802 Nm
[D]. 1604 Nm

Answer: Option C


No answer description available for this question.

Arul said: (Jun 19, 2017)  
Here, v2=0.01*401/(0.01+4)=1 then loss of kinetic energy=0.5*0.01*(401^2-1^2)=804.

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