Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 3 (Q.No. 13)
13.
A plan of an area drawn with the original scale of 1 cm = 10 m, has shrunk such that a line, originally 15 cm long on the plan, measures now 14.5 cm. The shrunk scale is given by 1 cm equal to
0.97 m
9.70 m
10.34 m
10.97 m
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

BASAVARAJA K M said:   1 decade ago
= 10*15 equals 150.

= 150/154.5 equals 10.34.

Jitender Singh said:   9 years ago
Since, true length =( wrong scale ÷ correct scale) * measured length.

Here now true length will be = 14.5 cm as we have to find the scale for it. Wrong scale will then be 10 and measured length 15.
14.5= (10 ÷correct scale) x 15.

Pawan said:   8 years ago
1cm =1000cm.
15cm = 15000cm.
14.5cm = 15000/14.5 = 1034.45152cm.
= 10.34m.

Sadashiva said:   8 years ago
Shrunk scale=original scale * shrinkage factor.
Shrinkage factor=Shrunk lenth/actual length.
=15/14.5.
=1.034.

Shrunk scale = 10 * 1.034.
= 10.34m.

Sinhmar gurbaksh singh said:   8 years ago
Nice explaination @Sadashiva.

Anand said:   7 years ago
Thanks for your explanation @Sadashiva.

Kaushiki mishra said:   6 years ago
Thanks for the answer @Pawan.

Gayathri said:   6 years ago
Thanks for the formula @Sadashiva.

Ankit singh said:   6 years ago
Shrunk factor = 145/150.
= 29/30.

Shrunk scale = original scale * SF.
= (1cm/1000cm) * (29/30).
= 1cm/ 1034cm.
Shrunk scale : 1cm = 10.30 m.
(1)

SHEHIN S RAHIM said:   6 years ago
SHRUNK SCALE = SF * OS.

SF = SL/OL = 14.5CM/15CM.

SS = SF * OS = (14.5/15)*(1/1000) = 1/(15000/14.5) = 1/1034.48CM.
In m it's 10.34.
(5)


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