Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 22 (Q.No. 16)
16.
A clay sample has a void ratio of 0.50 in dry state and specific gravity of solids = 2.70. Its shrinkage limit will be
Answer: Option
Explanation:
You can find the answer here.
http://www.meritanswers.com/questions/shrinkage-limit-of-a-clay-sample/13282-1-1
Discussion:
2 comments Page 1 of 1.
Arnav Bhai said:
4 years ago
Se = WG.
(S= 1 at Shrinkage Limit.)
1*0.5=W*2.7.
W=0.5/2.7,
i.e. W=18.5.
(Hint: W is related as shrinkage limit also depends on the water content.)
(S= 1 at Shrinkage Limit.)
1*0.5=W*2.7.
W=0.5/2.7,
i.e. W=18.5.
(Hint: W is related as shrinkage limit also depends on the water content.)
(1)
Amrit said:
8 years ago
Shrinkage limit(Ws)=void ratio/specific gravity =e/G.
0.50/2.70 = 0.185.
= 0.185 * 100= 18.51%.
0.50/2.70 = 0.185.
= 0.185 * 100= 18.51%.
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