Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 12 (Q.No. 1)
1.
A pipeline of 5 cm diameter is reduced abruptly to 2.5 cm diameter at a section to enable measurement of the water flowing through it. The loss of head at the contraction is 0.5 m. Given that, in metric units, 2g = 4.43 and g = 3.132, the mean velocity in the reduced section will be
Discussion:
4 comments Page 1 of 1.
R Krishna Chaitanya said:
7 months ago
@All.
We know that,
The head loss due to sudden contraction is approximately equal to (0.5v^2)/(2g).
then, 0.5 = (0.5v^2)/(2g),
v^2 = 2g, therefore, v = 4.43 m/s.
We know that,
The head loss due to sudden contraction is approximately equal to (0.5v^2)/(2g).
then, 0.5 = (0.5v^2)/(2g),
v^2 = 2g, therefore, v = 4.43 m/s.
(2)
M.AKILA said:
7 years ago
Please give the description of the answer.
Umesh H A said:
7 years ago
Head loss due to contraction is;
Head loss = (0.5 * V2 square)/2g.
Head loss = (0.5 * V2 square)/2g.
Dibakar said:
4 years ago
.5 = .5 * (V^2/2g).
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