Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 17 (Q.No. 50)
50.
Ratio of the width of the car parking area required at kerb for 30° parking relative to 60° parking is approximately
Discussion:
11 comments Page 1 of 2.
Krupal patel said:
2 years ago
60/30 = 2.0.
Susanta Sanyal said:
4 years ago
0.8 is the correct Answer.
(3)
Mir Imroz said:
4 years ago
Ratio of 30°parking to 60° parking is hsin30°/hsin60° = .50.
(1)
Kis said:
5 years ago
Yes, .8 is the correct one.
(2)
A ali said:
5 years ago
0.8 is the correct answer.
(1)
KAMALESH BISWAS said:
6 years ago
30°/60°=1/2=0.5.
Hardev chauhan said:
6 years ago
[Lsin60° +l/2sin30°]/[Lsin30° + l/2sin60°].
(L=6).
= [6sin60°+3sin30°]/[6sin30°+3sin60°],
= [6.206/7.281].
= 0.85 Ans.
(L=6).
= [6sin60°+3sin30°]/[6sin30°+3sin60°],
= [6.206/7.281].
= 0.85 Ans.
(1)
Subham Dutta said:
7 years ago
(5sin30+2.5sin30)/(5sin60+2.5sin60) =.577 ==.5 = A.
Roy said:
8 years ago
30°- 4.66 m. & 60°=5.58m.
So, ratio=(4.66/5.58)==0.8.
So, ratio=(4.66/5.58)==0.8.
(3)
Arul raj said:
8 years ago
L1 = xcos30°.
L2 = xcos60°.
L1/L2 = 1.732 = approximately equal to 2.
L2 = xcos60°.
L1/L2 = 1.732 = approximately equal to 2.
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