Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 4 (Q.No. 7)
7.
Four vertical columns of the same material, height and weight have the same end condition. The buckling load will be the largest for a column having the cross-section of a/an
Discussion:
10 comments Page 1 of 1.
Omer said:
7 years ago
I think buckling load will be the largest for a column having a large cross section.
Buckling load will be the smallest for a column having a small cross-section to buckle largest cross section, we need the largest load.
So, the Answer is Option A.
Buckling load will be the smallest for a column having a small cross-section to buckle largest cross section, we need the largest load.
So, the Answer is Option A.
(1)
ADD said:
9 years ago
Why not b?
Shashank mishra said:
8 years ago
B is right, because thin hollow circular sections are most efficient in resisting compression because their moment of inertia is maximum.
Manhar chavada said:
8 years ago
B is the right answer.
Dolly said:
7 years ago
I too think, B is the right answer.
MeeNA said:
7 years ago
B is the right answer.
Naren limbu said:
6 years ago
Pcr=(π) EI/le2.
Pcr is directly proportional to I(moi).
MOI of solid squire is greater than the circle. So PCR (buckling load)of the solid square is more than a circle. Therefore option A is correct.
Pcr is directly proportional to I(moi).
MOI of solid squire is greater than the circle. So PCR (buckling load)of the solid square is more than a circle. Therefore option A is correct.
Manoj Kumar said:
6 years ago
I think option D is correct, because Pcr depends upon MOI, Which is max. For I-section for the condition.
Laltu said:
3 years ago
The moment of inertia is maximum for the hollow circular section because the maximum mass, in this case, lies away from the centroidal axis as compared to all other cross sections.
Hence, the load-carrying capacity is maximum for a hollow circular section.
Hence, the load-carrying capacity is maximum for a hollow circular section.
Rahul verma said:
2 years ago
B is the correct answer.
According to Euler's formula.
Load is proportional to moment of inertia, here for hollow section it is more, so it carry more load.
According to Euler's formula.
Load is proportional to moment of inertia, here for hollow section it is more, so it carry more load.
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