Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 12 (Q.No. 11)
11.
A concentrated load acting on the surface of a soil produces a stress of 19.1 kPa at a depth of 1 m below it. Using Boussinesq's expression, the stress at 2 m depth is
Discussion:
4 comments Page 1 of 1.
Valmik Prajapati said:
1 year ago
Q1 = Q2.
σ1.z1 = σ2.z2
19.1 * (1)^2 = σ2*(2)^2.
σ2 = 19.1÷4.
σ2 = 4.775kPa.
σ1.z1 = σ2.z2
19.1 * (1)^2 = σ2*(2)^2.
σ2 = 19.1÷4.
σ2 = 4.775kPa.
Sakshi said:
5 years ago
First, calculate Q=19.1/0.4775 i.e. 40.
(Using formula) then for 2m depth σ(v)2 is 0.4775 * 40/2 square = 4.775 => Answer.
(Using formula) then for 2m depth σ(v)2 is 0.4775 * 40/2 square = 4.775 => Answer.
(1)
Phanindra said:
7 years ago
σ1 = 0.4775 * Q/z1^2 and also right σ2 = 0.4775*Q/z2^2.
Take ratio and will get 19.1÷4 = 4.775.
σ1 = 19.1,
Z1=1,
Z2=2,
σ2 = ?.
Take ratio and will get 19.1÷4 = 4.775.
σ1 = 19.1,
Z1=1,
Z2=2,
σ2 = ?.
DSP said:
8 years ago
Give Explanation.
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