Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 9 (Q.No. 8)
8.
A and B are two traverse stations free from local attraction errors. If the true bearing of a line AB is 89°, and the magnetic declination at point A is 1° West, then the magnetic bearing of the line BA would be
Discussion:
12 comments Page 1 of 2.
Balvinder Guleria said:
5 years ago
True bearing of AB=89°
BA = 180 + 89 = 269,
Megnetic declinations=1w(-ve).
TB = MB-MD.
269°= MB-1,
MB = 269 + 1,
MB = 270°.
BA = 180 + 89 = 269,
Megnetic declinations=1w(-ve).
TB = MB-MD.
269°= MB-1,
MB = 269 + 1,
MB = 270°.
(17)
Roy said:
8 years ago
Magnetic bearing of AB=89+1=90.
So magnetic bearing of BA=90+180=270.
So magnetic bearing of BA=90+180=270.
(2)
HUZAIF said:
4 years ago
270° is the right answer, as it is asking for MB of line BA and not AB.
(2)
Rahul verma said:
3 years ago
270° should be the correct answer.
(2)
Karan Kushwah said:
2 years ago
MB of BA =270°.
(2)
MD Aqeel Ahmed said:
7 years ago
MB of AB = 89-1 =88 (1° West).
Bearing of BA = 88+180= 268.
West means -.
East means +.
Bearing of BA = 88+180= 268.
West means -.
East means +.
(1)
Bongil said:
5 years ago
Magnetic bearing = true bearing +declination.
= true bearing + declination.
= 89+1= 90°.
= true bearing + declination.
= 89+1= 90°.
(1)
Vipul said:
9 years ago
The answer should be 270°.
Ramya said:
8 years ago
But how? Explain.
Sam said:
7 years ago
Yes, 270° is the correct answer.
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