Civil Engineering - UPSC Civil Service Exam Questions
Exercise : UPSC Civil Service Exam Questions - Section 21
- UPSC Civil Service Exam Questions - Section 14
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- UPSC Civil Service Exam Questions - Section 26
- UPSC Civil Service Exam Questions - Section 25
- UPSC Civil Service Exam Questions - Section 24
- UPSC Civil Service Exam Questions - Section 23
- UPSC Civil Service Exam Questions - Section 22
- UPSC Civil Service Exam Questions - Section 21
- UPSC Civil Service Exam Questions - Section 20
- UPSC Civil Service Exam Questions - Section 19
- UPSC Civil Service Exam Questions - Section 18
- UPSC Civil Service Exam Questions - Section 17
- UPSC Civil Service Exam Questions - Section 16
- UPSC Civil Service Exam Questions - Section 15
- UPSC Civil Service Exam Questions - Section 1
- UPSC Civil Service Exam Questions - Section 13
- UPSC Civil Service Exam Questions - Section 12
- UPSC Civil Service Exam Questions - Section 11
- UPSC Civil Service Exam Questions - Section 10
- UPSC Civil Service Exam Questions - Section 9
- UPSC Civil Service Exam Questions - Section 8
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- UPSC Civil Service Exam Questions - Section 6
- UPSC Civil Service Exam Questions - Section 5
- UPSC Civil Service Exam Questions - Section 4
- UPSC Civil Service Exam Questions - Section 3
- UPSC Civil Service Exam Questions - Section 2
36.
What is the permissible tensile stress is bolts used for column bases ?(Where fy is the yield stress of the steel)
37.
King closers are related to
38.
The area of a plot is to be determined using Simpson's rule. The following offsets were taken to a boundary from points along a chain line all measurements being in metres 12, 15, 22, 29, 36, 38, 31, 22, 17.There were taken at 100 m intervals.
Consider the following steps in this regard.
1.
2. Sum of the odd ordinates = 22 + 36 + 1 = 89
3. Sum of the even ordinates = 15 + 29 + 38 + 22 = 104
4. 12 + 17 = 39
5. Area = 100 (19.5 + 89 + 104)
6. Area =
(39 + 2 x 89 + 4 x 104)
7. Area 100 x 19.5 (104 - 89)
The area of the plot can be determined by using the steps listed above :
Consider the following steps in this regard.
1.

2. Sum of the odd ordinates = 22 + 36 + 1 = 89
3. Sum of the even ordinates = 15 + 29 + 38 + 22 = 104
4. 12 + 17 = 39
5. Area = 100 (19.5 + 89 + 104)
6. Area =

7. Area 100 x 19.5 (104 - 89)
The area of the plot can be determined by using the steps listed above :
39.
At a cross-section of a beam, the maximum compressive stress at top is 800 kg/cm2 and its maximum tensile stress at bottom is 200 kg/cm2. The depth of cross-section is 10 cm. The depth of the neutral axis from the top of the section is n. The n is equal to
40.
A buttress in a wall is intended to provide
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