Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 4 (Q.No. 32)
32.
In case of a simply supported I-section beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is
none of these.
Discussion:
8 comments Page 1 of 1.
Sahil Sanjeev Salvi said:
7 years ago
Loaded with a central load W:
L/8 for I section.
L/3 for Rectangular section.
Loaded with a U. D. load :
L/root 3 for Rectangular section.
L/8 for I section.
L/3 for Rectangular section.
Loaded with a U. D. load :
L/root 3 for Rectangular section.
Roy said:
7 years ago
Yes, it's l/8.
KUNWAR said:
6 years ago
Yes, you are right @Sahil.
Rajashri Kamalakar Sarode said:
6 years ago
Then, What is for a tubular section?
OPSC AEE said:
5 years ago
@Thank Sahil.
Answer - none of the above.
Answer - none of the above.
Ankit Pandey said:
3 years ago
For the I section it may vary;
If you take shape factor 1.2,
It comes out to be L/6,
Lp= L(1-1/S).
If you take shape factor 1.2,
It comes out to be L/6,
Lp= L(1-1/S).
B.Singh said:
3 years ago
L/8 is the right answer.
Vishal said:
3 months ago
The shape factor of I section is 1.22 and the elastic-plastic zone length L = l(1-1/shape factor).
Then we gate the value of l/5 with the help of the above formula.
Then we gate the value of l/5 with the help of the above formula.
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