Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 21)
21.
In case of a simply supported rectangular beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is
Discussion:
15 comments Page 1 of 2.
Kaushik said:
5 years ago
For I- section it is (L/5).
(4)
Just helping said:
2 years ago
For all shapes => L (1 - 1/shape factor).
(4)
Nitu said:
10 years ago
Length of plastic hinge = Distance between Mp and My.
You can use a formula too = L (1-(1/shape factor)).
Shape factor for rectangular = 1.5.
Plastic length = L/3.
You can use a formula too = L (1-(1/shape factor)).
Shape factor for rectangular = 1.5.
Plastic length = L/3.
(1)
Nungshi said:
7 years ago
Lp/L =(1-1/Ks) where Ks is shape factor. (For centrally concentrated load).
Lp/L = √(1-1/Ks) (for udl).
Lp/L = √(1-1/Ks) (for udl).
(1)
Anshul Gupta said:
1 decade ago
Shape factor = 1.5.
Plastic moment/elastic moment = 1.5.
1.5 = L/(2x).
x = L/3.
Plastic moment/elastic moment = 1.5.
1.5 = L/(2x).
x = L/3.
Arghya said:
1 decade ago
I have a problem in that why we consider the elastic moment as 2x?
Sagnik said:
1 decade ago
It is 1.5 = Mp/Me.
1.5 = (L/2)/X.
As plastic hinge will form at L/2.
1.5 = (L/2)/X.
As plastic hinge will form at L/2.
Zubair Ahmad said:
9 years ago
S.F = Plastic Moment/Elastic moment.
1.5(for rect. section) = L/2/x (plastic hinge at (L/2).
1.5 = L/2x.
x = L/1.5X2.
x = L/3.
1.5(for rect. section) = L/2/x (plastic hinge at (L/2).
1.5 = L/2x.
x = L/1.5X2.
x = L/3.
Rana Muhammad Ashraf said:
9 years ago
X is what distance? can anyone explain.
Chandan said:
9 years ago
X is the distance from one end to plastic hinge.
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