Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 21)
21.
In case of a simply supported rectangular beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is
Discussion:
15 comments Page 1 of 2.
Just helping said:
2 years ago
For all shapes => L (1 - 1/shape factor).
(4)
Yash said:
4 years ago
For I section L/9.
Kaushik said:
5 years ago
For I- section it is (L/5).
(4)
Vignesh said:
6 years ago
Can we call the ratio between plastic moment to elastic moment as the ELASTOPLASTIC zone?
OPSC AEE said:
6 years ago
For I-section - L/8.
Rectangular section - L/3.
Rectangular section - L/3.
Dhananjay said:
7 years ago
Thanks for explaining @Nitu.
Nungshi said:
7 years ago
Lp/L =(1-1/Ks) where Ks is shape factor. (For centrally concentrated load).
Lp/L = √(1-1/Ks) (for udl).
Lp/L = √(1-1/Ks) (for udl).
(1)
Steve said:
7 years ago
I think x is any distance along the beam where strain can occur under a considerable amount of stress. hence, the modulus of elasticity is applicable here. Also, L/2 is where ultimate failure is likely to occur and hence it is where the plastic hinge is located, hence, the plastic modulus is applicable here and that is the idea of having the ratio as 0.5L/X=1.5.
Therefore X=0.33333333L=L/3.
Therefore X=0.33333333L=L/3.
Chandan said:
9 years ago
X is the distance from one end to plastic hinge.
Rana Muhammad Ashraf said:
9 years ago
X is what distance? can anyone explain.
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