# Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 2 (Q.No. 33)

33.

A rectangular column shown in the given figure carries a load

*P*having eccentricities*e*and_{x}*e*along_{v}*X*and*Y*axes. The stress at any point (*x, y*) isDiscussion:

9 comments Page 1 of 1.
Saidur Rahman said:
2 years ago

In which case, the bending stress will be negative?

Please explain.

Please explain.

Anush M said:
5 years ago

In bending stress equation, why it is Ix in both the direction?

I think it should be Ix for Mx and Iy for My. If this statement is correct, then equation will be Combined stress =(P/A) + (Mx/Ix) + (My/Iy). Is this right? Please tell me.

I think it should be Ix for Mx and Iy for My. If this statement is correct, then equation will be Combined stress =(P/A) + (Mx/Ix) + (My/Iy). Is this right? Please tell me.

Monali said:
6 years ago

Thanks @Ranguwal.

Monali said:
6 years ago

Thanks @Ranguwal.

Ranguwal said:
6 years ago

In the denominator, it always to occur in a square within the bracket value because the load is in N or KN so, p/bd outside has the unit N/mm2 & in the bracket, mm2 should be needed so ONLY FIRST option gives the same units so think wisely>>::.

Harsha said:
7 years ago

Iy= db3 /12. So, in answer b2 should be for P * ey * y/ b2.

Raja said:
7 years ago

Thanks @Roshan.

Roshan said:
8 years ago

Normal stress = p/A.

Bending stress= Mx*y/Ix + My*x/Ix.

Adding both, P/A +M*Y/I .

where A=(b*d) and Mx= P*ey, My= P*ex, Ix= bd3/12; Iy=db3/12.

Bending stress= Mx*y/Ix + My*x/Ix.

Adding both, P/A +M*Y/I .

where A=(b*d) and Mx= P*ey, My= P*ex, Ix= bd3/12; Iy=db3/12.

(1)

Ranjit ray said:
8 years ago

How? Explain it clearly.

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