# Civil Engineering - Theory of Structures - Discussion

### Discussion :: Theory of Structures - Section 1 (Q.No.14)

14.

Keeping the depth d constant, the width of a cantilever of length l of uniform strength loaded with a uniformly distributed load w varies from zero at the free end and

 [A]. at the fixed end [B]. at the fixed end [C]. at the fixed end [D]. at the fixed end

Explanation:

No answer description available for this question.

 Anshul Gupta said: (Sep 25, 2013) Sigma denoted by S. And Z(section modulus) = bd2/6. Then, B.M. at fixed support is wl2/2. wl2/2 = S*Z. wl2/2 = S*bd2/6. b= (3wl2)/Sd2. Answer C.

 Nishant Jain said: (Oct 16, 2016) Thanks @Anshul Gupta.

 Mukesh Pal said: (Nov 4, 2016) Thank you @Anshul Gupta.

 Ravi said: (Nov 18, 2016) This is not uniform load so b.m is not (w*l^2)/2 varying load so b.m is (w*i^2)/6 answer.

 Akash said: (Jan 14, 2017) Yes, you are correct @Ravi.

 Patil said: (Mar 30, 2017) Yes, @Ravi You are correct, bm not wl^2/2. It is wl^2 /6 n final and is wl^2/(d^2*s).

 Vijay Kumar said: (May 29, 2017) None of the above answers is correct. The Answer will be wl2/sd2.

 Jeet Beniwal said: (Sep 21, 2017) You are wrong @Ravi. Load is udl. Width is o at free end. And asked the width at fix end.

 Lekhs said: (Dec 22, 2017) What is the right answer? Please explain me.

 Chandan said: (Apr 28, 2018) Thanks @Anshul.

 Dileep Pawaar said: (May 19, 2018) You are correct @Anshul Gupta.

 Narayan said: (Oct 23, 2018) s= σ(direct stress). M= wl^2-1/2*(l*w)*2/3(l) = wl^2/6. But, M=S * Z. wl^2/6 = S * b * d^2/6. b = wl^2/s * d^2.

 Nilraj. said: (Nov 20, 2018) @Ravi. This is uniformly Distributed load.

 Dhananjay said: (Feb 23, 2019) @Anshul, How can you equate BM with S*Z? Here, units are different. Please explain.

 Syed Mazhar said: (Dec 12, 2019) @Dhananjay. From bending eq M/I= f/y=E/R M=(I/y)f M=zf.

 Shubham Siddharth Nayak said: (Nov 19, 2020) Cantilever carrying UDL- BM at fixed end = wl^2 /2. We know, M = fz. Wl^2/2= f *(bd^2/6), b =3wl^2/fd^2.

 Michael said: (Apr 19, 2021) Thanks @Anshul Gupta.

 Bishwo said: (May 28, 2021) Bending moment at fixed =1/3 (wl^2) /2. 1/3 is because it's a triangular slab of thickness d and with b. 1 part of whole rectangle will give BM at the fixed end.

 Jeganathan said: (Aug 29, 2021) Sigma is nothing but f (bending stress). And Z(section modulus) = bd2/6. Then, B.M. at fixed support is wl2/2. M= f.(I/Y) M=f.Z wl2/2 = f * Z. wl2/2 = f * bd2/6. b= (3wl2)/fd2. Answer C.