# Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 1 (Q.No. 14)

14.

Keeping the depth

*d*constant, the width of a cantilever of length*l*of uniform strength loaded with a uniformly distributed load*w*varies from zero at the free end andDiscussion:

21 comments Page 1 of 3.
Abiy said:
9 months ago

The right Answer is A.

Abiy said:
9 months ago

@Gupta.

Thanks for your explanation but for load w uniformly distributed from free end zero.

W=wl/2.

Which it's Mmax=wl/3 At the fixed end.

So, the answer is C.

Thanks for your explanation but for load w uniformly distributed from free end zero.

W=wl/2.

Which it's Mmax=wl/3 At the fixed end.

So, the answer is C.

(1)

Jeganathan said:
2 years ago

Sigma is nothing but f (bending stress).

And Z(section modulus) = bd2/6.

Then,

B.M. at fixed support is wl2/2.

M= f.(I/Y)

M=f.Z

wl2/2 = f * Z.

wl2/2 = f * bd2/6.

b= (3wl2)/fd2.

Answer C.

And Z(section modulus) = bd2/6.

Then,

B.M. at fixed support is wl2/2.

M= f.(I/Y)

M=f.Z

wl2/2 = f * Z.

wl2/2 = f * bd2/6.

b= (3wl2)/fd2.

Answer C.

(3)

Bishwo said:
2 years ago

Bending moment at fixed =1/3 (wl^2) /2.

1/3 is because it's a triangular slab of thickness d and with b. 1 part of whole rectangle will give BM at the fixed end.

1/3 is because it's a triangular slab of thickness d and with b. 1 part of whole rectangle will give BM at the fixed end.

(1)

Michael said:
2 years ago

Thanks @Anshul Gupta.

SHUBHAM SIDDHARTH NAYAK said:
3 years ago

Cantilever carrying UDL- BM at fixed end = wl^2 /2.

We know, M = fz.

Wl^2/2= f *(bd^2/6),

b =3wl^2/fd^2.

We know, M = fz.

Wl^2/2= f *(bd^2/6),

b =3wl^2/fd^2.

Syed Mazhar said:
3 years ago

@Dhananjay.

From bending eq

M/I= f/y=E/R

M=(I/y)f

M=zf.

From bending eq

M/I= f/y=E/R

M=(I/y)f

M=zf.

Dhananjay said:
4 years ago

@Anshul,

How can you equate BM with S*Z? Here, units are different. Please explain.

How can you equate BM with S*Z? Here, units are different. Please explain.

Nilraj. said:
5 years ago

@Ravi.

This is uniformly Distributed load.

This is uniformly Distributed load.

Narayan said:
5 years ago

s= σ(direct stress).

M= wl^2-1/2*(l*w)*2/3(l)

= wl^2/6.

But,

M=S * Z.

wl^2/6 = S * b * d^2/6.

b = wl^2/s * d^2.

M= wl^2-1/2*(l*w)*2/3(l)

= wl^2/6.

But,

M=S * Z.

wl^2/6 = S * b * d^2/6.

b = wl^2/s * d^2.

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