Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 14)
14.
Keeping the depth d constant, the width of a cantilever of length l of uniform strength loaded with a uniformly distributed load w varies from zero at the free end and
Discussion:
23 comments Page 2 of 3.
Nilraj. said:
7 years ago
@Ravi.
This is uniformly Distributed load.
This is uniformly Distributed load.
Narayan said:
7 years ago
s= σ(direct stress).
M= wl^2-1/2*(l*w)*2/3(l)
= wl^2/6.
But,
M=S * Z.
wl^2/6 = S * b * d^2/6.
b = wl^2/s * d^2.
M= wl^2-1/2*(l*w)*2/3(l)
= wl^2/6.
But,
M=S * Z.
wl^2/6 = S * b * d^2/6.
b = wl^2/s * d^2.
Dileep pawaar said:
7 years ago
You are correct @Anshul Gupta.
Chandan said:
7 years ago
Thanks @Anshul.
Lekhs said:
8 years ago
What is the right answer? Please explain me.
Jeet Beniwal said:
8 years ago
You are wrong @Ravi.
Load is udl.
Width is o at free end.
And asked the width at fix end.
Load is udl.
Width is o at free end.
And asked the width at fix end.
Vijay kumar said:
8 years ago
None of the above answers is correct. The Answer will be wl2/sd2.
Patil said:
8 years ago
Yes, @Ravi
You are correct, bm not wl^2/2. It is wl^2 /6 n final and is wl^2/(d^2*s).
You are correct, bm not wl^2/2. It is wl^2 /6 n final and is wl^2/(d^2*s).
(1)
Akash said:
9 years ago
Yes, you are correct @Ravi.
Ravi said:
9 years ago
This is not uniform load so b.m is not (w*l^2)/2 varying load so b.m is (w*i^2)/6 answer.
(1)
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