Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 2 (Q.No. 2)
2.
The general expression for the B.M. of a beam of length l is the beam carries
Discussion:
5 comments Page 1 of 1.
M.D.RAHUL NAIK said:
10 years ago
I like it and we can improve our knowledge.
Somesh jain said:
9 years ago
Helpful session and questions, Thanks for posting this.
SHAMNAS MANDHIYIL said:
8 years ago
Take a section at X distance from the end A of the beam.
Ra=Rb= wl/2.
Calculate moment at X distance from A.
Mx = Ra . x - w . x . x /2 = wlx/2 - w x2/2.
Ra=Rb= wl/2.
Calculate moment at X distance from A.
Mx = Ra . x - w . x . x /2 = wlx/2 - w x2/2.
Steve said:
7 years ago
RA=RB= WL/2
Taking moment at a point Z, X distance from either support A or B gives: (Wx^2/2)-(WL/2)*x.
where:
Wx^2/2--------------> udl component.
(WL/2)*x-------------> reaction/support component.
Taking moment at a point Z, X distance from either support A or B gives: (Wx^2/2)-(WL/2)*x.
where:
Wx^2/2--------------> udl component.
(WL/2)*x-------------> reaction/support component.
Inayat Ullah Kakar said:
9 months ago
Solution:
Consider a simply supported beam:
UDL change into a point load.
w/l = WL.
Sum of vertical reaction=0
So, Ra = Rb = WL/2.
Now, take X distance from end A
Now take a moment on point X
The Sum of moment at point X = 0.
I.e For Clockwise+ and Anticlockwise -
-Mx + Ra * x-w * x * (x/2) = 0.
As; Ra = Wl/2.
Mx = Wl * x/2 - wx ^ 2/2.
Consider a simply supported beam:
UDL change into a point load.
w/l = WL.
Sum of vertical reaction=0
So, Ra = Rb = WL/2.
Now, take X distance from end A
Now take a moment on point X
The Sum of moment at point X = 0.
I.e For Clockwise+ and Anticlockwise -
-Mx + Ra * x-w * x * (x/2) = 0.
As; Ra = Wl/2.
Mx = Wl * x/2 - wx ^ 2/2.
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