Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 1 (Q.No. 5)
5.
The normal component of a force inclined through θ° is obtained by multiplying the force by
sin θ
cos θ
tan θ
sin θ cos θ
sin2θ
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Gyanendra said:   1 decade ago
Would you please let me know how it comes? I would be very grateful to you.

HanyIbraheem said:   1 decade ago
Sinθ for horizontal component and cosθ for vertical component.

Sawan said:   1 decade ago
Pleas tell me how it comes?

Raghuvesh tiwari said:   1 decade ago
But both component will not be normal. So?

Engr T Abioye said:   10 years ago
Sine θ is for the vertical i.e. normal and cos θ is for the horizontal components. If the angle of inclination is to the horizontal.

Sanjay said:   9 years ago
Let XY be the direction along which the given force is acting.

And we have to find the component of force in XZ direction.

It is given that the force is inclined at θ to the given plane (the plane is in between the XY and XZ line).

So component of F towards the given plane is F.Cosθ.

Now this F.Cosθ force is at an angle of (90-θ) to XZ.

Therefore its component towards XZ.

= F.Cosθ.Cos(90-θ).

= F.Cosθ.Sinθ.
(8)

Asaithambi said:   8 years ago
Horizontal vice force acting mention angle cosθ and vertical vice force acting mention angle is sinθ.

Russ said:   8 years ago
What are the elements or components that involve in the study of the theory of structure?

Mokhtar said:   8 years ago
It will differ if the angles between the 3 directions are different.

Keshav Raidas said:   8 years ago
Yes, right thanks @Sanjay.


Post your comments here:

Your comments will be displayed after verification.